AutoMore Automation

Set Warnings "-notation-overridden,-notation-incompatible-prefix".
From Stdlib Require Import Arith List.
From Stdlib Require Import Lia.
From Stdlib Require Import Strings.String.
From LF Require Import Maps.
From LF Require Import Imp.
Set Default Goal Selector "!".
Up to now, we've used the manual part of Rocq's tactic facilities. In this chapter, we'll learn more about some of Rocq's powerful automation features: proof search via the auto tactic, automated forward reasoning via the Ltac hypothesis matching machinery, and deferred instantiation of existential variables using eapply and eauto. Using these features together with Ltac's scripting facilities will enable us to make some of our proofs startlingly short! Used properly, they can also make proofs more maintainable and robust to changes in underlying definitions. A deeper treatment of auto and eauto can be found in the UseAuto chapter in Programming Language Foundations.
There's one other major category of automation we haven't discussed much yet, namely built-in decision procedures for specific kinds of problems: lia is one example, and at the end of the chapter we will introduce one more called congruence.
We start with the auto tactic, though, and our motivating example will be the following proof, repeated with just a few small changes from the Imp chapter. We will simplify this proof in several stages.
Theorem ceval_deterministic: c st st1 st2,
  st =[ c ]=> st1
  st =[ c ]=> st2
  st1 = st2.
Proof.
  intros c st st1 st2 E1 E2;
  generalize dependent st2;
  induction E1; intros st2 E2; inversion E2; subst.
  - (* E_Skip *) reflexivity.
  - (* E_Asgn *) reflexivity.
  - (* E_Seq *)
    rewrite (IHE1_1 st'0 H1) in ×.
    apply IHE1_2. assumption.
  (* E_IfTrue *)
  - (* b evaluates to true *)
    apply IHE1. assumption.
  - (* b evaluates to false (contradiction) *)
    rewrite H in H5. discriminate.
  (* E_IfFalse *)
  - (* b evaluates to true (contradiction) *)
    rewrite H in H5. discriminate.
  - (* b evaluates to false *)
    apply IHE1. assumption.
  (* E_WhileFalse *)
  - (* b evaluates to false *)
    reflexivity.
  - (* b evaluates to true (contradiction) *)
    rewrite H in H2. discriminate.
  (* E_WhileTrue *)
  - (* b evaluates to false (contradiction) *)
    rewrite H in H4. discriminate.
  - (* b evaluates to true *)
    rewrite (IHE1_1 st'0 H3) in ×.
    apply IHE1_2. assumption. Qed.

The auto Tactic

Thus far, our proof scripts mostly work backward by applying relevant hypotheses or lemmas to the goal by name, one at a time.
Example auto_example_1 : (P Q R: Prop),
  (P Q) (Q R) P R.
Proof.
  intros P Q R HPQ HQR HP.
  apply HQR. apply HPQ. assumption.
Qed.
The auto tactic tries to free us from this drudgery by searching for a sequence of applications to the goal that will finally prove it:
Example auto_example_1' : (P Q R: Prop),
  (P Q) (Q R) P R.
Proof.
  auto.
Qed.
The auto tactic solves goals that are solvable by any combination of intros and apply.
Using auto is always "safe" in the sense that it will never fail and will never change the proof state: either it completely solves the current goal, or it does nothing.
Here is a larger example showing auto's power:
Example auto_example_2 : P Q R S T U : Prop,
  (P Q)
  (P R)
  (T R)
  (S T U)
  ((P Q) (P S))
  T
  P
  U.
Proof. auto. Qed.
Intuitively, we can understand the auto tactic as recursively performing the following backward search steps:
  • If assumption closes the goal, we are done.
  • If the goal is an implication () or an universal quantifier (), call the intro tactic (the unary version of intros) and continue with the new goal.
  • Otherwise, apply a hypothesis whose conclusion unifies with the goal, and recurse on the new subgoals. If some subgoal cannot be closed, backtrack and try any other hypothesis unifying with the goal.
If no candidate path leads to a complete proof, auto does nothing, leaving the goal unchanged.
If auto does not solve our goal as expected we can use debug auto to see a trace. In fact, debug auto prints the whole search trace even when auto succeeds, so we can also use it to watch auto backtrack:
Example auto_algorithm : (P Q R: Prop),
  (Q R) (* HQR : requires Q -- dead end *)
  ((P P) R) (* HPPR : requires P P -- proved by intro
                                                    and assumption *)

  R.
Proof. intros P Q R HQR HPPR. debug auto. Qed.
Proof search could, in principle, take an arbitrarily long time, so there is a limit to how deep auto will search (by default 5).
Example auto_example_3 : (P Q R S T U: Prop),
  (P Q)
  (Q R)
  (R S)
  (S T)
  (T U)
  P
  U.
Proof.
  intros P Q R S T U HPQ HQR HRS HST HTU HP.
  (* auto does nothing for this goal, even if it seems solvable *)
  auto.

  (* Let's see what auto does with the default search depth
     of 5 by adding the debug keyword: *)

  debug auto.

  (* What it did is this: *)
  (* apply HTU. *)
  (* apply HST. *)
  (* apply HRS. *)
  (* apply HQR. *)
  (* apply HPQ. *)
  (* But then it couldn't prove P
     even though it had P as a hypothesis *)


  (* With an optional argument to auto we can change the maximum
     search depth; in this case a depth of 6 does the trick: *)

  auto 6.
Qed.
When searching for potential proofs of the current goal, auto considers the hypotheses in the current context together with a hint database of other lemmas and constructors. Some common lemmas about equality and logical operators are installed in this hint database by default.
Example auto_example_4 : P Q R : Prop,
  Q
  (Q R)
  P (Q R).
Proof. auto. Qed.
If we want to see which facts auto is using, we can use info_auto instead. As opposed to debug auto which also prints failed paths, info_auto only displays the successful proof path.
Example auto_example_4' : P Q R : Prop,
  Q
  (Q R)
  P (Q R).
Proof.
  info_auto.
Qed.
auto used the following facts from the default hint database:
Check or_intror : A B : Prop, B A B.
Check conj : A B : Prop, A B A B.

Example auto_example_5: 2 = 2.
Proof.
  info_auto.
Qed.
auto subsumes reflexivity because eq_refl is a fact in the default hint database:
Check @eq_refl : A (x:A), x = x.
We can extend the hint database just for the purposes of one application of auto by writing "auto using ...".
Lemma le_antisym : n m: nat, (n m m n) n = m.
Proof. lia. Qed.

Example auto_example_6 : n m p q : nat,
  (p = q (n m m n))
  p = q
  n = m.
Proof.
  auto using le_antisym.
Qed.
Of course, in any given development there will probably be some specific constructors and lemmas that are used very often in proofs. We can add these to the global hint database by writing
      Hint Resolve T : core. at the top level, where T is a top-level theorem or a constructor of an inductively defined proposition (i.e., anything whose type is an implication). As a shorthand, we can write
      Hint Constructors c : core. to tell Rocq to do a Hint Resolve for all of the constructors from the inductive definition of c.
It is also sometimes necessary to add
      Hint Unfold d : core. where d is a defined symbol, so that auto knows to unfold uses of d, thus enabling further possibilities for applying lemmas that it knows about.
It is also possible to define specialized hint databases (besides core) that can be activated only when needed; indeed, it is good style to create your own hint databases instead of polluting core.
See the Rocq reference manual for details.
Hint Resolve le_antisym : core.

Example auto_example_6' : n m p q : nat,
  (p = q (n m m n))
  p = q
  n = m.
Proof.
  auto. (* picks up hint from database *)
Qed.

Definition is_fortytwo x := (x = 42).

Example auto_example_7: x,
  (x 42 42 x) is_fortytwo x.
Proof.
  auto. (* does nothing *)
Abort.

Hint Unfold is_fortytwo : core.

Example auto_example_7' : x,
  (x 42 42 x) is_fortytwo x.
Proof.
  auto. (* try also: info_auto. *)
Qed.
Note that the Hint Unfold is_fortytwo command above the example is needed because, unlike the normal apply tactic, the simple apply steps that are performed by auto do not do any automatic unfolding.
Let's take a first pass over ceval_deterministic, using auto to simplify the proof script.
Theorem ceval_deterministic': c st st1 st2,
  st =[ c ]=> st1
  st =[ c ]=> st2
  st1 = st2.
Proof.
  intros c st st1 st2 E1 E2.
  generalize dependent st2.
  induction E1; intros st2 E2;
    inversion E2; subst; (* <- ends with ; *)
    auto. (* <---- here's one good place to try auto *)
  - (* E_Seq *)
    rewrite (IHE1_1 st'0 H1) in ×.
    auto. (* <---- here's another *)
  - (* E_IfTrue *)
    rewrite H in H5. discriminate.
  - (* E_IfFalse *)
    rewrite H in H5. discriminate.
  - (* E_WhileFalse *)
    rewrite H in H2. discriminate.
  - (* E_WhileTrue, with b false *)
    rewrite H in H4. discriminate.
  - (* E_WhileTrue, with b true *)
    rewrite (IHE1_1 st'0 H3) in ×.
    auto. (* <---- and another *)
Qed.
When we are using a particular tactic many times in a proof, we can use a variant of the Proof command to make that tactic into a default within the proof. Saying Proof with t (where t is an arbitrary tactic) allows us to use t1... as a shorthand for t1;t within the proof. As an illustration, here is an alternate version of the previous proof, using Proof with auto.
Theorem ceval_deterministic'_alt: c st st1 st2,
  st =[ c ]=> st1
  st =[ c ]=> st2
  st1 = st2.
Proof with auto.
  intros c st st1 st2 E1 E2.
  generalize dependent st2.
  induction E1; intros st2 E2;
    inversion E2; subst...
  - (* E_Seq *)
    rewrite (IHE1_1 st'0 H1) in ×...
  - (* E_IfTrue *)
    rewrite H in H5. discriminate.
  - (* E_IfFalse *)
    rewrite H in H5. discriminate.
  - (* E_WhileFalse *)
    rewrite H in H2. discriminate.
  - (* E_WhileTrue, with b false *)
    rewrite H in H4. discriminate.
  - (* E_WhileTrue, with b true *)
    rewrite (IHE1_1 st'0 H3) in ×...
Qed.

Exercises

From LF Require IndProp.

Module Exercises.

Import IndProp. Import Pumping.

Exercise: 1 star, standard (pumping_constant_ge_1_redux)

Use auto, lia, and ; to reprove this lemma in a "single" line. The "official" proof in IndProp takes about a dozen lines.
Lemma pumping_constant_ge_1 :
   T (re : reg_exp T),
    pumping_constant re 1.
(* FILL IN HERE *) Admitted.
(* Do not modify the following line: *)
Definition manual_grade_for_pumping_constant_ge_1_redux : option (nat×string) := None.

Regular Expression Optimization Exercise

Exercise: 3 stars, standard (re_opt_match_auto)

As a simple illustration of the benefits of automation, let's consider another problem on regular expressions, which we formalized in IndProp. A given set of strings can be denoted by many different regular expressions. For example, App EmptyString re matches exactly the same strings as re. We can write a function that "optimizes" any regular expression into a potentially simpler one by applying this fact throughout the r.e. (Note that, for simplicity, the function does not optimize expressions that arise as the result of other optimizations.)
Fixpoint re_opt {T:Type} (re: reg_exp T) : reg_exp T :=
  match re with
  | App _ EmptySetEmptySet
  | App EmptyStr re2re_opt re2
  | App re1 EmptyStrre_opt re1
  | App re1 re2App (re_opt re1) (re_opt re2)
  | Union EmptySet re2re_opt re2
  | Union re1 EmptySetre_opt re1
  | Union re1 re2Union (re_opt re1) (re_opt re2)
  | Star EmptySetEmptyStr
  | Star EmptyStrEmptyStr
  | Star reStar (re_opt re)
  | EmptySetEmptySet
  | EmptyStrEmptyStr
  | Char xChar x
  end.
We would like to show the equivalence of re's with their "optimized" form. Here is an incredibly tedious manual proof of (one direction of) its correctness:
Lemma re_opt_match : T (re: reg_exp T) s,
  s =~ re s =~ re_opt re.
Proof.
  intros T re s M.
  induction M
    as [| x'
       | s1 re1 s2 re2 Hmatch1 IH1 Hmatch2 IH2
       | s1 re1 re2 Hmatch IH | s2 re1 re2 Hmatch IH
       | re | s1 s2 re Hmatch1 IH1 Hmatch2 IH2].
  - (* MEmpty *) simpl. apply MEmpty.
  - (* MChar *) simpl. apply MChar.
  - (* MApp *) simpl.
    destruct re1.
    + inversion IH1.
    + inversion IH1. simpl. destruct re2.
      × apply IH2.
      × apply IH2.
      × apply IH2.
      × apply IH2.
      × apply IH2.
      × apply IH2.
    + destruct re2.
      × inversion IH2.
      × inversion IH2. rewrite app_nil_r. apply IH1.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
    + destruct re2.
      × inversion IH2.
      × inversion IH2. rewrite app_nil_r. apply IH1.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
    + destruct re2.
      × inversion IH2.
      × inversion IH2. rewrite app_nil_r. apply IH1.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
    + destruct re2.
      × inversion IH2.
      × inversion IH2. rewrite app_nil_r. apply IH1.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
      × apply MApp.
        -- apply IH1.
        -- apply IH2.
  - (* MUnionL *) simpl.
    destruct re1.
    + inversion IH.
    + destruct re2.
      × apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
    + destruct re2.
      × apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
    + destruct re2.
      × apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
    + destruct re2.
      × apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
    + destruct re2.
      × apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
      × apply MUnionL. apply IH.
  - (* MUnionR *) simpl.
    destruct re1.
    + apply IH.
    + destruct re2.
      × inversion IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
    + destruct re2.
      × inversion IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
    + destruct re2.
      × inversion IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
    + destruct re2.
      × inversion IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
    + destruct re2.
      × inversion IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
      × apply MUnionR. apply IH.
 - (* MStar0 *) simpl.
    destruct re.
    + apply MEmpty.
    + apply MEmpty.
    + apply MStar0.
    + apply MStar0.
    + apply MStar0.
    + simpl.
      destruct re.
      × apply MStar0.
      × apply MStar0.
      × apply MStar0.
      × apply MStar0.
      × apply MStar0.
      × apply MStar0.
 - (* MStarApp *) simpl.
   destruct re.
   + inversion IH1.
   + inversion IH1. inversion IH2. apply MEmpty.
   + apply star_app.
     × apply MStar1. apply IH1.
     × apply IH2.
   + apply star_app.
     × apply MStar1. apply IH1.
     × apply IH2.
   + apply star_app.
     × apply MStar1. apply IH1.
     × apply IH2.
   + apply star_app.
     × apply MStar1. apply IH1.
     × apply IH2.
Qed.
Use auto to shorten the proof. The proof above is about 200 lines. Reduce it to 50 or fewer lines of similar density. Eliminate all uses of apply, thus removing the need to name specific constructors and lemmas about regular expressions.
Hint: You can use a bottom-up approach. First copy-paste the entire proof below. Then automate the innermost bullets first, proceeding outwards. Frequently double-check that the entire proof still compiles. If it doesn't, undo the most recent changes you made until you get back to a compiling proof.
Lemma re_opt_match'' : T (re: reg_exp T) s,
  s =~ re s =~ re_opt re.
Proof.
(* FILL IN HERE *) Admitted.
(* Do not modify the following line: *)
Definition manual_grade_for_re_opt_match'' : option (nat×string) := None.

Optional Pumping Exercise

Exercise: 3 stars, advanced, optional (pumping_redux_strong)

Use auto, lia, repeat, ;, try, etc. to shorten the official proof of the stronger Pumping Lemma optional exercise from IndProp.
Lemma pumping : T (re : reg_exp T) s,
    s =~ re
    pumping_constant re length s
     s1 s2 s3,
      s = s1 ++ s2 ++ s3
        s2 []
        length s1 + length s2 pumping_constant re
         m, s1 ++ napp m s2 ++ s3 =~ re.
Proof.
  (* FILL IN HERE *) Admitted.
(* Do not modify the following line: *)
Definition manual_grade_for_pumping_redux_strong : option (nat×string) := None.
End Exercises.

Searching For Hypotheses

The proof has become simpler, but there is still an annoying degree of repetition. Let's start by tackling the contradiction cases. Each of them occurs in a situation where we have both
      H1: beval st b = false and
      H2: beval st b = true as hypotheses. The contradiction is evident, but demonstrating it is a little complicated: we have to locate the two hypotheses H1 and H2 and do a rewrite following by a discriminate. We'd like to automate this process.
(In fact, Rocq has a built-in tactic congruence that will do the job in this case. We'll ignore this tactic for now, in order to demonstrate how to build forward-search tactics by hand.)
As a first step, we can abstract out the piece of script in question by writing a little function in Ltac.
Ltac rwd H1 H2 := rewrite H1 in H2; discriminate.

Theorem ceval_deterministic'': c st st1 st2,
  st =[ c ]=> st1
  st =[ c ]=> st2
  st1 = st2.
Proof.
  intros c st st1 st2 E1 E2.
  generalize dependent st2;
  induction E1; intros st2 E2; inversion E2; subst; auto.
  - (* E_Seq *)
    rewrite (IHE1_1 st'0 H1) in ×.
    auto.
  - (* E_IfTrue *)
    rwd H H5. (* <----- *)
  - (* E_IfFalse *)
    rwd H H5. (* <----- *)
  - (* E_WhileFalse *)
    rwd H H2. (* <----- *)
  - (* E_WhileTrue - b false *)
    rwd H H4. (* <----- *)
  - (* EWhileTrue - b true *)
    rewrite (IHE1_1 st'0 H3) in ×.
    auto. Qed.
That's a bit better, but we really want Rocq to discover the relevant hypotheses for us. We can do this by using the match goal facility of Ltac.
Ltac find_rwd :=
  match goal with
    H1: ?E = true, H2: ?E = false_
       ⇒
    rwd H1 H2
  end.
This match goal looks for two distinct hypotheses that have the form of equalities, with the same arbitrary expression E on the left and with conflicting boolean values on the right. If such hypotheses are found, it binds H1 and H2 to their names and applies the rwd tactic to H1 and H2.
Adding this tactic to the ones that we invoke in each case of the induction handles all of the contradictory cases.
Theorem ceval_deterministic''': c st st1 st2,
  st =[ c ]=> st1
  st =[ c ]=> st2
  st1 = st2.
Proof.
  intros c st st1 st2 E1 E2.
  generalize dependent st2;
  induction E1; intros st2 E2; inversion E2; subst;
       try find_rwd; (* <------ *)
       auto.
  - (* E_Seq *)
    rewrite (IHE1_1 st'0 H1) in ×.
    auto.
  - (* E_WhileTrue - b true *)
    rewrite (IHE1_1 st'0 H3) in ×.
    auto. Qed.
Let's see about the remaining cases. Each of them involves rewriting a hypothesis after feeding it with the required condition. We can automate the task of finding the relevant hypotheses to rewrite with.
Ltac find_eqn :=
  match goal with
    H1: x, ?P x ?L = ?R,
    H2: ?P ?X
    ⊢ _
    ⇒ rewrite (H1 X H2) in ×
  end.
The pattern x, ?P x ?L = ?R matches any hypothesis of the form "for all x, some property of x implies some equality." The property of x is bound to the pattern variable P, and the left- and right-hand sides of the equality are bound to L and R. The name of this hypothesis is bound to H1. Then the pattern ?P ?X matches any hypothesis that provides evidence that P holds for some concrete X. If both patterns succeed, we apply the rewrite tactic (instantiating the quantified x with X and providing H2 as the required evidence for P X) in all hypotheses and the goal.
Theorem ceval_deterministic'''': c st st1 st2,
  st =[ c ]=> st1
  st =[ c ]=> st2
  st1 = st2.
Proof.
  intros c st st1 st2 E1 E2.
  generalize dependent st2;
  induction E1; intros st2 E2; inversion E2; subst;
    try find_rwd;
    try find_eqn; (* <------- *)
    auto.
Qed.
The big payoff in this approach is that the new proof script is more robust in the face of changes to our language. To test this, let's try adding a REPEAT command to the language.
Module Repeat.

Inductive com : Type :=
  | CSkip
  | CAsgn (x : string) (a : aexp)
  | CSeq (c1 c2 : com)
  | CIf (b : bexp) (c1 c2 : com)
  | CWhile (b : bexp) (c : com)
  | CRepeat (c : com) (b : bexp).
REPEAT behaves like while, except that the loop guard is checked after each execution of the body, with the loop repeating as long as the guard stays false. Because of this, the body will always execute at least once.
Notation "'repeat' x 'until' y 'end'" :=
         (CRepeat x y)
            (in custom com at level 0,
             x at level 99, y at level 99).
Notation "'skip'" :=
         CSkip (in custom com at level 0).
Notation "x := y" :=
         (CAsgn x y)
            (in custom com at level 0, x constr at level 0,
             y at level 85, no associativity).
Notation "x ; y" :=
         (CSeq x y)
           (in custom com at level 90, right associativity).
Notation "'if' x 'then' y 'else' z 'end'" :=
         (CIf x y z)
           (in custom com at level 89, x at level 99,
            y at level 99, z at level 99).
Notation "'while' x 'do' y 'end'" :=
         (CWhile x y)
            (in custom com at level 89, x at level 99, y at level 99).

Reserved Notation "st '=[' c ']=>' st'"
         (at level 40, c custom com at level 99, st' constr at next level).

Inductive ceval : com state state Prop :=
  | E_Skip : st,
      st =[ skip ]=> st
  | E_Asgn : st a1 n x,
      aeval st a1 = n
      st =[ x := a1 ]=> (x !-> n ; st)
  | E_Seq : c1 c2 st st' st'',
      st =[ c1 ]=> st'
      st' =[ c2 ]=> st''
      st =[ c1 ; c2 ]=> st''
  | E_IfTrue : st st' b c1 c2,
      beval st b = true
      st =[ c1 ]=> st'
      st =[ if b then c1 else c2 end ]=> st'
  | E_IfFalse : st st' b c1 c2,
      beval st b = false
      st =[ c2 ]=> st'
      st =[ if b then c1 else c2 end ]=> st'
  | E_WhileFalse : b st c,
      beval st b = false
      st =[ while b do c end ]=> st
  | E_WhileTrue : st st' st'' b c,
      beval st b = true
      st =[ c ]=> st'
      st' =[ while b do c end ]=> st''
      st =[ while b do c end ]=> st''
  | E_RepeatEnd : st st' b c,
      st =[ c ]=> st'
      beval st' b = true
      st =[ repeat c until b end ]=> st'
  | E_RepeatLoop : st st' st'' b c,
      st =[ c ]=> st'
      beval st' b = false
      st' =[ repeat c until b end ]=> st''
      st =[ repeat c until b end ]=> st''

  where "st =[ c ]=> st'" := (ceval c st st').
Our first attempt at the determinacy proof does not quite succeed: the E_RepeatEnd and E_RepeatLoop cases are not handled by our previous automation.
Theorem ceval_deterministic: c st st1 st2,
  st =[ c ]=> st1
  st =[ c ]=> st2
  st1 = st2.
Proof.
  intros c st st1 st2 E1 E2.
  generalize dependent st2;
  induction E1;
    intros st2 E2; inversion E2; subst; try find_rwd; try find_eqn; auto.
  - (* E_RepeatEnd *)
    + (* b evaluates to false (contradiction) *)
       find_rwd.
       (* oops: why didn't find_rwd solve this for us already?
          answer: we did things in the wrong order. *)

  - (* E_RepeatLoop *)
     + (* b evaluates to true (contradiction) *)
        find_rwd.
Qed.
Fortunately, to fix this, we just have to swap the invocations of find_eqn and find_rwd.
Theorem ceval_deterministic': c st st1 st2,
  st =[ c ]=> st1
  st =[ c ]=> st2
  st1 = st2.
Proof.
  intros c st st1 st2 E1 E2.
  generalize dependent st2;
  induction E1;
    intros st2 E2; inversion E2; subst; try find_eqn; try find_rwd; auto.
Qed.

End Repeat.
These examples just give a flavor of what "hyper-automation" can achieve in Rocq. The details of match goal are a bit tricky (and debugging scripts using it is, frankly, not very pleasant). But it is well worth adding at least simple uses to your proofs, both to avoid tedium and to "future proof" them.

The eapply and eauto tactics

To close the chapter, let's look at one more convenience feature of Rocq: its ability to delay instantiation of quantifiers. To motivate this feature, recall this example from the Imp chapter:
Example ceval_example1:
  empty_st =[
    X := 2;
    if (X 1)
      then Y := 3
      else Z := 4
    end
  ]=> (Z !-> 4 ; X !-> 2).
Proof.
  (* We supply the intermediate state st'... *)
  apply E_Seq with (st' := X !-> 2).
  - apply E_Asgn. reflexivity.
  - apply E_IfFalse.
    + reflexivity.
    + apply E_Asgn. reflexivity.
Qed.
In the first step of the proof, we had to explicitly provide a longish expression to help Rocq instantiate a "hidden" argument to the E_Seq constructor. This was needed because the definition of E_Seq...
          E_Seq : c1 c2 st st' st'',
            st =[ c1 ]=> st'
            st' =[ c2 ]=> st''
            st =[ c1 ; c2 ]=> st''
is quantified over a variable, st', that does not appear in its conclusion, so unifying its conclusion with the goal state doesn't help Rocq find a suitable value for this variable. If we leave out the with, this step fails ("Error: Unable to find an instance for the variable st'").
What's silly about this error is that the appropriate value for st' will actually become obvious in the very next step, where we apply E_Asgn. If Rocq could just wait until we get to this step, there would be no need for us to give the value explicitly. This is exactly what the eapply tactic allows:
Example ceval'_example1:
  empty_st =[
    X := 2;
    if (X 1)
      then Y := 3
      else Z := 4
    end
  ]=> (Z !-> 4 ; X !-> 2).
Proof.
  (* 1 *) eapply E_Seq. (* introduces ?st' existential variable *)
  - (* 2 *) apply E_Asgn. (* instantiates ?st' with X !-> ?n;
                       using a fresh existential variable ?n *)

    (* 3 *) simpl. reflexivity. (* instantiates ?n with 2 *)
  - (* 4 *) apply E_IfFalse.
    + reflexivity.
    + apply E_Asgn. reflexivity.
Qed.
The eapply H tactic behaves just like apply H except that, after it finishes unifying the goal state with the conclusion of H, it skips checking whether all the variables that were introduced in the process have been given concrete values during unification.
If you step through the proof above, you'll see that the goal state at position 1 mentions the existential variable ?st' in both of the generated subgoals. The next step (which gets us to position 2) replaces ?st' with a concrete value. This new value contains a new existential variable ?n, which is instantiated in its turn by the following reflexivity step, position 3. When we start working on the second subgoal (position 4), we observe that the occurrence of ?st' in this subgoal has been replaced by the value that it was given during the first subgoal.
Several of the tactics that we've seen so far, including , constructor, and auto, have variants similar to eapply.
For instance, in addition to Rocq also provides an eexists tactic. To prove a goal of the form x, P x, the t tactic requires us to supply a concrete term t, changing the goal to P t. The eexists tactic instead introduces a fresh existential variable ?x in its place, leaving us with the goal P ?x. The value of ?x has to be determined by unification in some later proof step.
Example eexists_example : s',
  (Y !-> 1 ; X !-> 2) =[
    if (X Y)
      then Z := Y - X
      else Y := X + Z
    end
  ]=> s'.
Proof.
  eexists. eapply E_IfFalse.
  - reflexivity.
  - eapply E_Asgn. reflexivity.
Qed.
Similarly, econstructor is to constructor what eapply is to apply. In the proof of ceval'_example1, we could have written econstructor in place of eapply E_Seq: Rocq would pick the matching constructor (E_Seq) and leave the intermediate state as an existential variable, to be determined by a later step. Here is that proof again, using econstructor.
Example econstructor_example :
  empty_st =[
    X := 2;
    if (X 1)
      then Y := 3
      else Z := 4
    end
  ]=> (Z !-> 4 ; X !-> 2).
Proof.
  econstructor.
  - apply E_Asgn. reflexivity.
  - apply E_IfFalse.
    + reflexivity.
    + apply E_Asgn. reflexivity.
Qed.
The eauto tactic works like auto, except that it uses eapply instead of apply. Before using it in an example, we give some hints to eauto about using the constructors of ceval and the definitions of state and total_map as part of its proof search.
Hint Constructors ceval : core.
(* HIDE CH: I think better would be to choose another example that
   doesn't need `Hint Transparent` *)

Hint Transparent state total_map : core.

Example eauto_example : s',
  (Y !-> 1 ; X !-> 2) =[
    if (X Y)
      then Z := Y - X
      else Y := X + Z
    end
  ]=> s'.
Proof. info_eauto. Qed.
info_eauto shows us which facts eauto uses.
Pro tip: One might think that, since eapply and eauto are more powerful than apply and auto, we should just use them all the time. Unfortunately, they are also significantly slower especially eauto. Rocq experts tend to use apply and auto most of the time, only switching to the e variants when the ordinary variants don't do the job.

Constraints on Existential Variables

In order for Qed to succeed, all existential variables need to be determined by the end of the proof. Otherwise Rocq will (rightly) refuse to accept the proof. Remember that the Rocq tactics build proof objects, and proof objects containing existential variables are not complete.
Lemma silly1 : (P : nat nat Prop) (Q : nat Prop),
  ( x y : nat, P x y)
  ( x y : nat, P x y Q x)
  Q 42.
Proof.
  intros P Q HP HQ. eapply HQ. apply HP. Unshelve. exact 0.
Rocq gives a warning after apply HP: "All the remaining goals are on the shelf," means that we've finished all our top-level proof obligations but along the way we've put some aside to be done later, and we have not finished those. Trying to close the proof with Qed would yield an error. (Try it!)
Abort.
An additional constraint is that existential variables cannot be instantiated with terms containing ordinary variables that did not exist at the time the existential variable was created. (The reason for this technical restriction is that allowing such instantiation would lead to inconsistency of Rocq's logic.)
Lemma silly2 :
   (P : nat nat Prop) (Q : nat Prop),
  ( y, P 42 y)
  ( x y : nat, P x y Q x)
  Q 42.
Proof.
  intros P Q HP HQ. eapply HQ. destruct HP as [y HP'].
  Fail apply HP'.
The error we get, with some details elided, is:
      cannot instantiate "?y" because "y" is not in its scope In this case there is an easy fix: doing destruct HP before doing eapply HQ.
Abort.

Lemma silly2_fixed :
   (P : nat nat Prop) (Q : nat Prop),
  ( y, P 42 y)
  ( x y : nat, P x y Q x)
  Q 42.
Proof.
  intros P Q HP HQ. destruct HP as [y HP'].
  eapply HQ. apply HP'.
Qed.
The apply HP' in the last step unifies the existential variable in the goal with the variable y.
Note that the assumption tactic doesn't work in this case, since it cannot handle existential variables. However, Rocq also provides an eassumption tactic that solves the goal if one of the premises matches the goal up to instantiations of existential variables. We can use it instead of apply HP' if we like.
Lemma silly2_eassumption : (P : nat nat Prop) (Q : nat Prop),
  ( y, P 42 y)
  ( x y : nat, P x y Q x)
  Q 42.
Proof.
  intros P Q HP HQ. destruct HP as [y HP']. eapply HQ. eassumption.
Qed.
The eauto tactic will use eapply and eassumption, streamlining the proof even further.
Lemma silly2_eauto : (P : nat nat Prop) (Q : nat Prop),
  ( y, P 42 y)
  ( x y : nat, P x y Q x)
  Q 42.
Proof.
  intros P Q HP HQ. destruct HP as [y HP']. eauto.
Qed.

Solver for Equalities: The congruence Tactic

Rocq has several special-purpose tactics that can solve certain kinds of goals automatically, based on algorithms for specific mathematical or logical domains. One of these tactics, lia, were already introduced in Imp, and here we will learn one more: congruence.
The lia tactic makes use of facts about addition and multiplication to prove equalities. A more basic way of treating such formulas is to regard every function appearing in them as a black box: nothing is known about the function's behavior. Based on the properties of equality itself, it is still possible to prove some formulas. For example, y = f x g y = g (f x), even if we know nothing about f or g:
Theorem eq_example1 :
   (A B C : Type) (f : A B) (g : B C) (x : A) (y : B),
    y = f x g y = g (f x).
Proof.
  intros. rewrite H. reflexivity.
Qed.
The essential properties of equality are that it is:
  • reflexive
  • symmetric
  • transitive
  • a congruence: it respects function and predicate application.
It is that congruence property that we're using when we rewrite in the proof above: if a = b then f a = f b. (The ProofObjects chapter explores this idea further under the name "Leibniz equality".)
The congruence tactic is a decision procedure for equality with uninterpreted functions and other symbols.
Theorem eq_example1' :
   (A B C : Type) (f : A B) (g : B C) (x : A) (y : B),
    y = f x g y = g (f x).
Proof.
  congruence.
Qed.
The congruence tactic is able to work with constructors, even taking advantage of their injectivity and distinctness.
Theorem eq_example2 : (n m o p : nat),
    (n, o) = (m, p)
    n = m.
Proof.
  congruence.
Qed.

Theorem eq_example3 : (X : Type) (h : X) (t : list X),
    nil h :: t.
Proof.
  congruence.
Qed.
This gives us another way to simplify our determinism proof, which gets quite short even without using custom tactics:
Theorem ceval_deterministic_congruence: c st st1 st2,
  st =[ c ]=> st1
  st =[ c ]=> st2
  st1 = st2.
Proof.
  intros c st st1 st2 E1 E2.
  generalize dependent st2.
  induction E1; intros st2 E2;
    inversion E2; subst;
    auto;
    try congruence. (* <---- this solves 4 cases, previously proved
                             by rewrite and discriminate *)

  - (* E_Seq *)
    rewrite (IHE1_1 st'0 H1) in ×.
    auto.
  - (* E_WhileTrue, with b true *)
    rewrite (IHE1_1 st'0 H3) in ×.
    auto.
Qed.

Exercise: 2 stars, standard (automatic_solvers)

The exercises below could be proved with (relatively) long manual proof scripts, but each can be solved with just a single invocation of an automatic solver we learned about (congruence or lia).
Theorem cons_equal : {X} (n m: X) (l: list X),
    n = m n :: l = m :: l.
Proof. (* FILL IN HERE *) Admitted.

Theorem plus_le_cancel_r : n m p : nat,
    n + p m + p n m.
Proof. (* FILL IN HERE *) Admitted.

Theorem no_half : n,
    2 × n 1.
Proof. (* FILL IN HERE *) Admitted.

Theorem pair_equal : {X} (a b c d: X) (e: X × X),
    (a, (b, c)) = (d, e)
    e = (d, c)
    b = d.
Proof. (* FILL IN HERE *) Admitted.
(* 2026-08-24 10:03 *)