# AutoMore Automation

Set Warnings "-notation-overridden,-parsing".

Require Import Coq.omega.Omega.

From LF Require Import Maps.

From LF Require Import Imp.

Require Import Coq.omega.Omega.

From LF Require Import Maps.

From LF Require Import Imp.

Up to now, we've used the more manual part of Coq's tactic
facilities. In this chapter, we'll learn more about some of Coq's
powerful automation features: proof search via the auto tactic,
automated forward reasoning via the Ltac hypothesis matching
machinery, and deferred instantiation of existential variables
using eapply and eauto. Using these features together with
Ltac's scripting facilities will enable us to make our proofs
startlingly short! Used properly, they can also make proofs more
maintainable and robust to changes in underlying definitions. A
deeper treatment of auto and eauto can be found in the
UseAuto chapter in
There's another major category of automation we haven't discussed
much yet, namely built-in decision procedures for specific kinds
of problems: omega is one example, but there are others. This
topic will be deferred for a while longer.
Our motivating example will be this proof, repeated with just a
few small changes from the Imp chapter. We will simplify
this proof in several stages.
First, define a little Ltac macro to compress a common
pattern into a single command.

*Programming Language Foundations*.
Ltac inv H := inversion H; subst; clear H.

Theorem ceval_deterministic: ∀ c st st

c / st \\ st

c / st \\ st

st

Proof.

intros c st st

generalize dependent st

induction E

- (* E_Skip *) reflexivity.

- (* E_Ass *) reflexivity.

- (* E_Seq *)

assert (st' = st'0) as EQ

{ (* Proof of assertion *) apply IHE1_1; apply H

subst st'0.

apply IHE1_2. assumption.

(* E_IfTrue *)

- (* b evaluates to true *)

apply IHE1. assumption.

- (* b evaluates to false (contradiction) *)

rewrite H in H

(* E_IfFalse *)

- (* b evaluates to true (contradiction) *)

rewrite H in H

- (* b evaluates to false *)

apply IHE1. assumption.

(* E_WhileFalse *)

- (* b evaluates to false *)

reflexivity.

- (* b evaluates to true (contradiction) *)

rewrite H in H

(* E_WhileTrue *)

- (* b evaluates to false (contradiction) *)

rewrite H in H

- (* b evaluates to true *)

assert (st' = st'0) as EQ

{ (* Proof of assertion *) apply IHE1_1; assumption. }

subst st'0.

apply IHE1_2. assumption. Qed.

Theorem ceval_deterministic: ∀ c st st

_{1}st_{2},c / st \\ st

_{1}→c / st \\ st

_{2}→st

_{1}= st_{2}.Proof.

intros c st st

_{1}st_{2}E_{1}E_{2};generalize dependent st

_{2};induction E

_{1}; intros st_{2}E_{2}; inv E_{2}.- (* E_Skip *) reflexivity.

- (* E_Ass *) reflexivity.

- (* E_Seq *)

assert (st' = st'0) as EQ

_{1}.{ (* Proof of assertion *) apply IHE1_1; apply H

_{1}. }subst st'0.

apply IHE1_2. assumption.

(* E_IfTrue *)

- (* b evaluates to true *)

apply IHE1. assumption.

- (* b evaluates to false (contradiction) *)

rewrite H in H

_{5}. inversion H_{5}.(* E_IfFalse *)

- (* b evaluates to true (contradiction) *)

rewrite H in H

_{5}. inversion H_{5}.- (* b evaluates to false *)

apply IHE1. assumption.

(* E_WhileFalse *)

- (* b evaluates to false *)

reflexivity.

- (* b evaluates to true (contradiction) *)

rewrite H in H

_{2}. inversion H_{2}.(* E_WhileTrue *)

- (* b evaluates to false (contradiction) *)

rewrite H in H

_{4}. inversion H_{4}.- (* b evaluates to true *)

assert (st' = st'0) as EQ

_{1}.{ (* Proof of assertion *) apply IHE1_1; assumption. }

subst st'0.

apply IHE1_2. assumption. Qed.

# The auto Tactic

Example auto_example_1 : ∀ (P Q R: Prop),

(P → Q) → (Q → R) → P → R.

Proof.

intros P Q R H

apply H

Qed.

(P → Q) → (Q → R) → P → R.

Proof.

intros P Q R H

_{1}H_{2}H_{3}.apply H

_{2}. apply H_{1}. assumption.Qed.

The auto tactic frees us from this drudgery by

*searching*for a sequence of applications that will prove the goal:
Example auto_example_1' : ∀ (P Q R: Prop),

(P → Q) → (Q → R) → P → R.

Proof.

auto.

Qed.

(P → Q) → (Q → R) → P → R.

Proof.

auto.

Qed.

The auto tactic solves goals that are solvable by any combination of
Using auto is always "safe" in the sense that it will never fail
and will never change the proof state: either it completely solves
the current goal, or it does nothing.
Here is a more interesting example showing auto's power:

- intros and
- apply (of hypotheses from the local context, by default).

Example auto_example_2 : ∀ P Q R S T U : Prop,

(P → Q) →

(P → R) →

(T → R) →

(S → T → U) →

((P→Q) → (P→S)) →

T →

P →

U.

Proof. auto. Qed.

(P → Q) →

(P → R) →

(T → R) →

(S → T → U) →

((P→Q) → (P→S)) →

T →

P →

U.

Proof. auto. Qed.

Proof search could, in principle, take an arbitrarily long time,
so there are limits to how far auto will search by default.

Example auto_example_3 : ∀ (P Q R S T U: Prop),

(P → Q) →

(Q → R) →

(R → S) →

(S → T) →

(T → U) →

P →

U.

Proof.

(* When it cannot solve the goal, auto does nothing *)

auto.

(* Optional argument says how deep to search (default is 5) *)

auto 6.

Qed.

(P → Q) →

(Q → R) →

(R → S) →

(S → T) →

(T → U) →

P →

U.

Proof.

(* When it cannot solve the goal, auto does nothing *)

auto.

(* Optional argument says how deep to search (default is 5) *)

auto 6.

Qed.

When searching for potential proofs of the current goal,
auto considers the hypotheses in the current context together
with a

*hint database*of other lemmas and constructors. Some common lemmas about equality and logical operators are installed in this hint database by default.
Example auto_example_4 : ∀ P Q R : Prop,

Q →

(Q → R) →

P ∨ (Q ∧ R).

Proof. auto. Qed.

Q →

(Q → R) →

P ∨ (Q ∧ R).

Proof. auto. Qed.

We can extend the hint database just for the purposes of one
application of auto by writing "auto using ...".

Lemma le_antisym : ∀ n m: nat, (n ≤ m ∧ m ≤ n) → n = m.

Proof. intros. omega. Qed.

Example auto_example_6 : ∀ n m p : nat,

(n ≤ p → (n ≤ m ∧ m ≤ n)) →

n ≤ p →

n = m.

Proof.

intros.

auto using le_antisym.

Qed.

Proof. intros. omega. Qed.

Example auto_example_6 : ∀ n m p : nat,

(n ≤ p → (n ≤ m ∧ m ≤ n)) →

n ≤ p →

n = m.

Proof.

intros.

auto using le_antisym.

Qed.

Of course, in any given development there will probably be
some specific constructors and lemmas that are used very often in
proofs. We can add these to the global hint database by writing
It is also sometimes necessary to add
It is also possible to define specialized hint databases that can
be activated only when needed. See the Coq reference manual for
more.

Hint Resolve T.

at the top level, where T is a top-level theorem or a
constructor of an inductively defined proposition (i.e., anything
whose type is an implication). As a shorthand, we can write
Hint Constructors c.

to tell Coq to do a Hint Resolve for *all*of the constructors from the inductive definition of c.
Hint Unfold d.

where d is a defined symbol, so that auto knows to expand uses
of d, thus enabling further possibilities for applying lemmas that
it knows about.
Hint Resolve le_antisym.

Example auto_example_6' : ∀ n m p : nat,

(n≤ p → (n ≤ m ∧ m ≤ n)) →

n ≤ p →

n = m.

Proof.

intros.

auto. (* picks up hint from database *)

Qed.

Definition is_fortytwo x := (x = 42).

Example auto_example_7: ∀ x,

(x ≤ 42 ∧ 42 ≤ x) → is_fortytwo x.

Proof.

auto. (* does nothing *)

Abort.

Hint Unfold is_fortytwo.

Example auto_example_7' : ∀ x,

(x ≤ 42 ∧ 42 ≤ x) → is_fortytwo x.

Proof. auto. Qed.

Example auto_example_6' : ∀ n m p : nat,

(n≤ p → (n ≤ m ∧ m ≤ n)) →

n ≤ p →

n = m.

Proof.

intros.

auto. (* picks up hint from database *)

Qed.

Definition is_fortytwo x := (x = 42).

Example auto_example_7: ∀ x,

(x ≤ 42 ∧ 42 ≤ x) → is_fortytwo x.

Proof.

auto. (* does nothing *)

Abort.

Hint Unfold is_fortytwo.

Example auto_example_7' : ∀ x,

(x ≤ 42 ∧ 42 ≤ x) → is_fortytwo x.

Proof. auto. Qed.

Let's take a first pass over ceval_deterministic to simplify the
proof script.

Theorem ceval_deterministic': ∀ c st st

c / st \\ st

c / st \\ st

st

Proof.

intros c st st

generalize dependent st

induction E

- (* E_Seq *)

assert (st' = st'0) as EQ

subst st'0.

auto.

- (* E_IfTrue *)

+ (* b evaluates to false (contradiction) *)

rewrite H in H

- (* E_IfFalse *)

+ (* b evaluates to true (contradiction) *)

rewrite H in H

- (* E_WhileFalse *)

+ (* b evaluates to true (contradiction) *)

rewrite H in H

(* E_WhileTrue *)

- (* b evaluates to false (contradiction) *)

rewrite H in H

- (* b evaluates to true *)

assert (st' = st'0) as EQ

subst st'0.

auto.

Qed.

_{1}st_{2},c / st \\ st

_{1}→c / st \\ st

_{2}→st

_{1}= st_{2}.Proof.

intros c st st

_{1}st_{2}E_{1}E_{2}.generalize dependent st

_{2};induction E

_{1}; intros st_{2}E_{2}; inv E_{2}; auto.- (* E_Seq *)

assert (st' = st'0) as EQ

_{1}by auto.subst st'0.

auto.

- (* E_IfTrue *)

+ (* b evaluates to false (contradiction) *)

rewrite H in H

_{5}. inversion H_{5}.- (* E_IfFalse *)

+ (* b evaluates to true (contradiction) *)

rewrite H in H

_{5}. inversion H_{5}.- (* E_WhileFalse *)

+ (* b evaluates to true (contradiction) *)

rewrite H in H

_{2}. inversion H_{2}.(* E_WhileTrue *)

- (* b evaluates to false (contradiction) *)

rewrite H in H

_{4}. inversion H_{4}.- (* b evaluates to true *)

assert (st' = st'0) as EQ

_{1}by auto.subst st'0.

auto.

Qed.

When we are using a particular tactic many times in a proof, we
can use a variant of the Proof command to make that tactic into
a default within the proof. Saying Proof with t (where t is
an arbitrary tactic) allows us to use t

_{1}... as a shorthand for t_{1};t within the proof. As an illustration, here is an alternate version of the previous proof, using Proof with auto.
Theorem ceval_deterministic'_alt: ∀ c st st

c / st \\ st

c / st \\ st

st

_{1}st_{2},c / st \\ st

_{1}→c / st \\ st

_{2}→st

_{1}= st_{2}.
Proof with auto.

intros c st st

generalize dependent st

induction E

intros st

- (* E_Seq *)

assert (st' = st'0) as EQ

subst st'0...

- (* E_IfTrue *)

+ (* b evaluates to false (contradiction) *)

rewrite H in H

- (* E_IfFalse *)

+ (* b evaluates to true (contradiction) *)

rewrite H in H

- (* E_WhileFalse *)

+ (* b evaluates to true (contradiction) *)

rewrite H in H

(* E_WhileTrue *)

- (* b evaluates to false (contradiction) *)

rewrite H in H

- (* b evaluates to true *)

assert (st' = st'0) as EQ

subst st'0...

Qed.

intros c st st

_{1}st_{2}E_{1}E_{2};generalize dependent st

_{2};induction E

_{1};intros st

_{2}E_{2}; inv E_{2}...- (* E_Seq *)

assert (st' = st'0) as EQ

_{1}...subst st'0...

- (* E_IfTrue *)

+ (* b evaluates to false (contradiction) *)

rewrite H in H

_{5}. inversion H_{5}.- (* E_IfFalse *)

+ (* b evaluates to true (contradiction) *)

rewrite H in H

_{5}. inversion H_{5}.- (* E_WhileFalse *)

+ (* b evaluates to true (contradiction) *)

rewrite H in H

_{2}. inversion H_{2}.(* E_WhileTrue *)

- (* b evaluates to false (contradiction) *)

rewrite H in H

_{4}. inversion H_{4}.- (* b evaluates to true *)

assert (st' = st'0) as EQ

_{1}...subst st'0...

Qed.

# Searching For Hypotheses

H

and
_{1}: beval st b = false
H

as hypotheses. The contradiction is evident, but demonstrating it
is a little complicated: we have to locate the two hypotheses H_{2}: beval st b = true_{1}and H

_{2}and do a rewrite following by an inversion. We'd like to automate this process.

Ltac rwinv H

Theorem ceval_deterministic'': ∀ c st st

c / st \\ st

c / st \\ st

st

Proof.

intros c st st

generalize dependent st

induction E

- (* E_Seq *)

assert (st' = st'0) as EQ

subst st'0.

auto.

- (* E_IfTrue *)

+ (* b evaluates to false (contradiction) *)

rwinv H H

- (* E_IfFalse *)

+ (* b evaluates to true (contradiction) *)

rwinv H H

- (* E_WhileFalse *)

+ (* b evaluates to true (contradiction) *)

rwinv H H

(* E_WhileTrue *)

- (* b evaluates to false (contradiction) *)

rwinv H H

- (* b evaluates to true *)

assert (st' = st'0) as EQ

subst st'0.

auto. Qed.

_{1}H_{2}:= rewrite H_{1}in H_{2}; inv H_{2}.Theorem ceval_deterministic'': ∀ c st st

_{1}st_{2},c / st \\ st

_{1}→c / st \\ st

_{2}→st

_{1}= st_{2}.Proof.

intros c st st

_{1}st_{2}E_{1}E_{2}.generalize dependent st

_{2};induction E

_{1}; intros st_{2}E_{2}; inv E_{2}; auto.- (* E_Seq *)

assert (st' = st'0) as EQ

_{1}by auto.subst st'0.

auto.

- (* E_IfTrue *)

+ (* b evaluates to false (contradiction) *)

rwinv H H

_{5}.- (* E_IfFalse *)

+ (* b evaluates to true (contradiction) *)

rwinv H H

_{5}.- (* E_WhileFalse *)

+ (* b evaluates to true (contradiction) *)

rwinv H H

_{2}.(* E_WhileTrue *)

- (* b evaluates to false (contradiction) *)

rwinv H H

_{4}.- (* b evaluates to true *)

assert (st' = st'0) as EQ

_{1}by auto.subst st'0.

auto. Qed.

That was a bit better, but we really want Coq to discover the
relevant hypotheses for us. We can do this by using the match
goal facility of Ltac.

Ltac find_rwinv :=

match goal with

H

H

|- _ ⇒ rwinv H

end.

match goal with

H

_{1}: ?E = true,H

_{2}: ?E = false|- _ ⇒ rwinv H

_{1}H_{2}end.

This match goal looks for two distinct hypotheses that
have the form of equalities, with the same arbitrary expression
E on the left and with conflicting boolean values on the right.
If such hypotheses are found, it binds H
Adding this tactic to the ones that we invoke in each case of the
induction handles all of the contradictory cases.

_{1}and H_{2}to their names and applies the rwinv tactic to H_{1}and H_{2}.
Theorem ceval_deterministic''': ∀ c st st

c / st \\ st

c / st \\ st

st

Proof.

intros c st st

generalize dependent st

induction E

- (* E_Seq *)

assert (st' = st'0) as EQ

subst st'0.

auto.

- (* E_WhileTrue *)

+ (* b evaluates to true *)

assert (st' = st'0) as EQ

subst st'0.

auto. Qed.

_{1}st_{2},c / st \\ st

_{1}→c / st \\ st

_{2}→st

_{1}= st_{2}.Proof.

intros c st st

_{1}st_{2}E_{1}E_{2}.generalize dependent st

_{2};induction E

_{1}; intros st_{2}E_{2}; inv E_{2}; try find_rwinv; auto.- (* E_Seq *)

assert (st' = st'0) as EQ

_{1}by auto.subst st'0.

auto.

- (* E_WhileTrue *)

+ (* b evaluates to true *)

assert (st' = st'0) as EQ

_{1}by auto.subst st'0.

auto. Qed.

Let's see about the remaining cases. Each of them involves
applying a conditional hypothesis to extract an equality.
Currently we have phrased these as assertions, so that we have to
predict what the resulting equality will be (although we can then
use auto to prove it). An alternative is to pick the relevant
hypotheses to use and then rewrite with them, as follows:

Theorem ceval_deterministic'''': ∀ c st st

c / st \\ st

c / st \\ st

st

Proof.

intros c st st

generalize dependent st

induction E

- (* E_Seq *)

rewrite (IHE1_1 st'0 H

- (* E_WhileTrue *)

+ (* b evaluates to true *)

rewrite (IHE1_1 st'0 H

_{1}st_{2},c / st \\ st

_{1}→c / st \\ st

_{2}→st

_{1}= st_{2}.Proof.

intros c st st

_{1}st_{2}E_{1}E_{2}.generalize dependent st

_{2};induction E

_{1}; intros st_{2}E_{2}; inv E_{2}; try find_rwinv; auto.- (* E_Seq *)

rewrite (IHE1_1 st'0 H

_{1}) in *. auto.- (* E_WhileTrue *)

+ (* b evaluates to true *)

rewrite (IHE1_1 st'0 H

_{3}) in *. auto. Qed.
Now we can automate the task of finding the relevant hypotheses to
rewrite with.

Ltac find_eqn :=

match goal with

H

H

|- _ ⇒ rewrite (H

end.

match goal with

H

_{1}: ∀ x, ?P x → ?L = ?R,H

_{2}: ?P ?X|- _ ⇒ rewrite (H

_{1}X H_{2}) in *end.

The pattern ∀x, ?P x → ?L = ?R matches any hypothesis of
the form "for all x,
One problem remains: in general, there may be several pairs of
hypotheses that have the right general form, and it seems tricky
to pick out the ones we actually need. A key trick is to realize
that we can

*some property of x*implies*some equality*." The property of x is bound to the pattern variable P, and the left- and right-hand sides of the equality are bound to L and R. The name of this hypothesis is bound to H_{1}. Then the pattern ?P ?X matches any hypothesis that provides evidence that P holds for some concrete X. If both patterns succeed, we apply the rewrite tactic (instantiating the quantified x with X and providing H_{2}as the required evidence for P X) in all hypotheses and the goal.*try them all*! Here's how this works:- each execution of match goal will keep trying to find a valid pair of hypotheses until the tactic on the RHS of the match succeeds; if there are no such pairs, it fails;
- rewrite will fail given a trivial equation of the form X = X;
- we can wrap the whole thing in a repeat, which will keep doing useful rewrites until only trivial ones are left.

Theorem ceval_deterministic''''': ∀ c st st

c / st \\ st

c / st \\ st

st

Proof.

intros c st st

generalize dependent st

induction E

repeat find_eqn; auto.

Qed.

_{1}st_{2},c / st \\ st

_{1}→c / st \\ st

_{2}→st

_{1}= st_{2}.Proof.

intros c st st

_{1}st_{2}E_{1}E_{2}.generalize dependent st

_{2};induction E

_{1}; intros st_{2}E_{2}; inv E_{2}; try find_rwinv;repeat find_eqn; auto.

Qed.

The big payoff in this approach is that our proof script should be
more robust in the face of modest changes to our language. To
test whether it really is, let's try adding a REPEAT command to
the language.

Module Repeat.

Inductive com : Type :=

| CSkip : com

| CAsgn : string → aexp → com

| CSeq : com → com → com

| CIf : bexp → com → com → com

| CWhile : bexp → com → com

| CRepeat : com → bexp → com.

Inductive com : Type :=

| CSkip : com

| CAsgn : string → aexp → com

| CSeq : com → com → com

| CIf : bexp → com → com → com

| CWhile : bexp → com → com

| CRepeat : com → bexp → com.

REPEAT behaves like WHILE, except that the loop guard is
checked

*after*each execution of the body, with the loop repeating as long as the guard stays*false*. Because of this, the body will always execute at least once.
Notation "'SKIP'" :=

CSkip.

Notation "c

(CSeq c

Notation "X '::=' a" :=

(CAsgn X a) (at level 60).

Notation "'WHILE' b 'DO' c 'END'" :=

(CWhile b c) (at level 80, right associativity).

Notation "'IFB' e

(CIf e

Notation "'REPEAT' e

(CRepeat e

Inductive ceval : state → com → state → Prop :=

| E_Skip : ∀ st,

ceval st SKIP st

| E_Ass : ∀ st a

aeval st a

ceval st (X ::= a

| E_Seq : ∀ c

ceval st c

ceval st' c

ceval st (c

| E_IfTrue : ∀ st st' b

beval st b

ceval st c

ceval st (IFB b

| E_IfFalse : ∀ st st' b

beval st b

ceval st c

ceval st (IFB b

| E_WhileFalse : ∀ b

beval st b

ceval st (WHILE b

| E_WhileTrue : ∀ st st' st'' b

beval st b

ceval st c

ceval st' (WHILE b

ceval st (WHILE b

| E_RepeatEnd : ∀ st st' b

ceval st c

beval st' b

ceval st (CRepeat c

| E_RepeatLoop : ∀ st st' st'' b

ceval st c

beval st' b

ceval st' (CRepeat c

ceval st (CRepeat c

Notation "c

(at level 40, st at level 39).

CSkip.

Notation "c

_{1}; c_{2}" :=(CSeq c

_{1}c_{2}) (at level 80, right associativity).Notation "X '::=' a" :=

(CAsgn X a) (at level 60).

Notation "'WHILE' b 'DO' c 'END'" :=

(CWhile b c) (at level 80, right associativity).

Notation "'IFB' e

_{1}'THEN' e_{2}'ELSE' e_{3}'FI'" :=(CIf e

_{1}e_{2}e_{3}) (at level 80, right associativity).Notation "'REPEAT' e

_{1}'UNTIL' b_{2}'END'" :=(CRepeat e

_{1}b_{2}) (at level 80, right associativity).Inductive ceval : state → com → state → Prop :=

| E_Skip : ∀ st,

ceval st SKIP st

| E_Ass : ∀ st a

_{1}n X,aeval st a

_{1}= n →ceval st (X ::= a

_{1}) (t_update st X n)| E_Seq : ∀ c

_{1}c_{2}st st' st'',ceval st c

_{1}st' →ceval st' c

_{2}st'' →ceval st (c

_{1}; c_{2}) st''| E_IfTrue : ∀ st st' b

_{1}c_{1}c_{2},beval st b

_{1}= true →ceval st c

_{1}st' →ceval st (IFB b

_{1}THEN c_{1}ELSE c_{2}FI) st'| E_IfFalse : ∀ st st' b

_{1}c_{1}c_{2},beval st b

_{1}= false →ceval st c

_{2}st' →ceval st (IFB b

_{1}THEN c_{1}ELSE c_{2}FI) st'| E_WhileFalse : ∀ b

_{1}st c_{1},beval st b

_{1}= false →ceval st (WHILE b

_{1}DO c_{1}END) st| E_WhileTrue : ∀ st st' st'' b

_{1}c_{1},beval st b

_{1}= true →ceval st c

_{1}st' →ceval st' (WHILE b

_{1}DO c_{1}END) st'' →ceval st (WHILE b

_{1}DO c_{1}END) st''| E_RepeatEnd : ∀ st st' b

_{1}c_{1},ceval st c

_{1}st' →beval st' b

_{1}= true →ceval st (CRepeat c

_{1}b_{1}) st'| E_RepeatLoop : ∀ st st' st'' b

_{1}c_{1},ceval st c

_{1}st' →beval st' b

_{1}= false →ceval st' (CRepeat c

_{1}b_{1}) st'' →ceval st (CRepeat c

_{1}b_{1}) st''.Notation "c

_{1}'/' st '\\' st'" := (ceval st c_{1}st')(at level 40, st at level 39).

Our first attempt at the determinacy proof does not quite succeed:
the E_RepeatEnd and E_RepeatLoop cases are not handled by our
previous automation.

Theorem ceval_deterministic: ∀ c st st

c / st \\ st

c / st \\ st

st

Proof.

intros c st st

generalize dependent st

induction E

intros st

- (* E_RepeatEnd *)

+ (* b evaluates to false (contradiction) *)

find_rwinv.

(* oops: why didn't find_rwinv solve this for us already?

answer: we did things in the wrong order. *)

- (* E_RepeatLoop *)

+ (* b evaluates to true (contradiction) *)

find_rwinv.

Qed.

_{1}st_{2},c / st \\ st

_{1}→c / st \\ st

_{2}→st

_{1}= st_{2}.Proof.

intros c st st

_{1}st_{2}E_{1}E_{2}.generalize dependent st

_{2};induction E

_{1};intros st

_{2}E_{2}; inv E_{2}; try find_rwinv; repeat find_eqn; auto.- (* E_RepeatEnd *)

+ (* b evaluates to false (contradiction) *)

find_rwinv.

(* oops: why didn't find_rwinv solve this for us already?

answer: we did things in the wrong order. *)

- (* E_RepeatLoop *)

+ (* b evaluates to true (contradiction) *)

find_rwinv.

Qed.

Fortunately, to fix this, we just have to swap the invocations of
find_eqn and find_rwinv.

Theorem ceval_deterministic': ∀ c st st

c / st \\ st

c / st \\ st

st

Proof.

intros c st st

generalize dependent st

induction E

intros st

Qed.

End Repeat.

_{1}st_{2},c / st \\ st

_{1}→c / st \\ st

_{2}→st

_{1}= st_{2}.Proof.

intros c st st

_{1}st_{2}E_{1}E_{2}.generalize dependent st

_{2};induction E

_{1};intros st

_{2}E_{2}; inv E_{2}; repeat find_eqn; try find_rwinv; auto.Qed.

End Repeat.

These examples just give a flavor of what "hyper-automation"
can achieve in Coq. The details of match goal are a bit
tricky (and debugging scripts using it is, frankly, not very
pleasant). But it is well worth adding at least simple uses to
your proofs, both to avoid tedium and to "future proof" them.
To close the chapter, we'll introduce one more convenient feature
of Coq: its ability to delay instantiation of quantifiers. To
motivate this feature, recall this example from the Imp
chapter:

## The eapply and eauto variants

Example ceval_example1:

(X ::= 2;;

IFB X ≤ 1

THEN Y ::= 3

ELSE Z ::= 4

FI)

/ { --> 0 }

\\ { X --> 2 ; Z --> 4 }.

Proof.

(* We supply the intermediate state st'... *)

apply E_Seq with { X --> 2 }.

- apply E_Ass. reflexivity.

- apply E_IfFalse. reflexivity. apply E_Ass. reflexivity.

Qed.

(X ::= 2;;

IFB X ≤ 1

THEN Y ::= 3

ELSE Z ::= 4

FI)

/ { --> 0 }

\\ { X --> 2 ; Z --> 4 }.

Proof.

(* We supply the intermediate state st'... *)

apply E_Seq with { X --> 2 }.

- apply E_Ass. reflexivity.

- apply E_IfFalse. reflexivity. apply E_Ass. reflexivity.

Qed.

In the first step of the proof, we had to explicitly provide a
longish expression to help Coq instantiate a "hidden" argument to
the E_Seq constructor. This was needed because the definition
of E_Seq...
What's silly about this error is that the appropriate value for st'
will actually become obvious in the very next step, where we apply
E_Ass. If Coq could just wait until we get to this step, there
would be no need to give the value explicitly. This is exactly what
the eapply tactic gives us:

E_Seq : ∀ c

c

c

(c

is quantified over a variable, st', that does not appear in its
conclusion, so unifying its conclusion with the goal state doesn't
help Coq find a suitable value for this variable. If we leave
out the with, this step fails ("Error: Unable to find an
instance for the variable st'").
_{1}c_{2}st st' st'',c

_{1}/ st \\ st' →c

_{2}/ st' \\ st'' →(c

_{1};; c_{2}) / st \\ st''
Example ceval'_example1:

(X ::= 2;;

IFB X ≤ 1

THEN Y ::= 3

ELSE Z ::= 4

FI)

/ { --> 0 }

\\ { X --> 2 ; Z --> 4 }.

Proof.

eapply E_Seq. (* 1 *)

- apply E_Ass. (* 2 *)

reflexivity. (* 3 *)

- (* 4 *) apply E_IfFalse. reflexivity. apply E_Ass. reflexivity.

Qed.

(X ::= 2;;

IFB X ≤ 1

THEN Y ::= 3

ELSE Z ::= 4

FI)

/ { --> 0 }

\\ { X --> 2 ; Z --> 4 }.

Proof.

eapply E_Seq. (* 1 *)

- apply E_Ass. (* 2 *)

reflexivity. (* 3 *)

- (* 4 *) apply E_IfFalse. reflexivity. apply E_Ass. reflexivity.

Qed.

The eapply H tactic behaves just like apply H except
that, after it finishes unifying the goal state with the
conclusion of H, it does not bother to check whether all the
variables that were introduced in the process have been given
concrete values during unification.
If you step through the proof above, you'll see that the goal
state at position 1 mentions the
Several of the tactics that we've seen so far, including ∃,
constructor, and auto, have e... variants. For example,
here's a proof using eauto:

*existential variable*?st' in both of the generated subgoals. The next step (which gets us to position 2) replaces ?st' with a concrete value. This new value contains a new existential variable ?n, which is instantiated in its turn by the following reflexivity step, position 3. When we start working on the second subgoal (position 4), we observe that the occurrence of ?st' in this subgoal has been replaced by the value that it was given during the first subgoal.
Hint Constructors ceval.

Hint Transparent state.

Hint Transparent total_map.

Definition st

Definition st

Example eauto_example : ∃ s',

(IFB X ≤ Y

THEN Z ::= Y - X

ELSE Y ::= X + Z

FI) / st

Proof. eauto. Qed.

Hint Transparent state.

Hint Transparent total_map.

Definition st

_{12}:= { X --> 1 ; Y --> 2 }.Definition st

_{21}:= { X --> 2 ; Y --> 1 }.Example eauto_example : ∃ s',

(IFB X ≤ Y

THEN Z ::= Y - X

ELSE Y ::= X + Z

FI) / st

_{21}\\ s'.Proof. eauto. Qed.

The eauto tactic works just like auto, except that it uses
eapply instead of apply.
Pro tip: One might think that, since eapply and eauto are more
powerful than apply and auto, it would be a good idea to use
them all the time. Unfortunately, they are also significantly
slower — especially eauto. Coq experts tend to use apply and
auto most of the time, only switching to the e variants when
the ordinary variants don't do the job.